6k^2+94k-32=0

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Solution for 6k^2+94k-32=0 equation: 



6k^2+94k-32=0

a = 6; b = 94; c = -32;
Δ = b2-4ac
Δ = 942-4·6·(-32)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9604}=98$


$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(94)-98}{2*6}=\frac{-192}{12}
=-16
$


$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(94)+98}{2*6}=\frac{4}{12}
=1/3
$

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